Base | Representation |
---|---|
bin | 110000001010101110… |
… | …1000011101101010001 |
3 | 100212222212000110121211 |
4 | 1200111131003231101 |
5 | 3143320410412001 |
6 | 115304100020121 |
7 | 10321214205361 |
oct | 1402535035521 |
9 | 325885013554 |
10 | 103439154001 |
11 | 3a960784437 |
12 | 18069691641 |
13 | 99a6194001 |
14 | 5013b009a1 |
15 | 2a56128351 |
hex | 1815743b51 |
103439154001 has 2 divisors, whose sum is σ = 103439154002. Its totient is φ = 103439154000.
The previous prime is 103439153953. The next prime is 103439154037. The reversal of 103439154001 is 100451934301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102467211025 + 971942976 = 320105^2 + 31176^2 .
It is an emirp because it is prime and its reverse (100451934301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103439154001 - 211 = 103439151953 is a prime.
It is not a weakly prime, because it can be changed into another prime (103430154001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51719577000 + 51719577001.
It is an arithmetic number, because the mean of its divisors is an integer number (51719577001).
Almost surely, 2103439154001 is an apocalyptic number.
It is an amenable number.
103439154001 is a deficient number, since it is larger than the sum of its proper divisors (1).
103439154001 is an equidigital number, since it uses as much as digits as its factorization.
103439154001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 103439154001 in words is "one hundred three billion, four hundred thirty-nine million, one hundred fifty-four thousand, one".
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