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10344011213 is a prime number
BaseRepresentation
bin10011010001000110…
…10001010111001101
3222200220002012210102
421220203101113031
5132141031324323
64430232020445
7514222434044
oct115043212715
928626065712
1010344011213
114428a197a8
122008231725
13c8b0577c3
14701b1155b
154081b2328
hex2688d15cd

10344011213 has 2 divisors, whose sum is σ = 10344011214. Its totient is φ = 10344011212.

The previous prime is 10344011207. The next prime is 10344011231. The reversal of 10344011213 is 31211044301.

Together with next prime (10344011231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7589545924 + 2754465289 = 87118^2 + 52483^2 .

It is a cyclic number.

It is not a de Polignac number, because 10344011213 - 218 = 10343749069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10344011413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5172005606 + 5172005607.

It is an arithmetic number, because the mean of its divisors is an integer number (5172005607).

Almost surely, 210344011213 is an apocalyptic number.

It is an amenable number.

10344011213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10344011213 is an equidigital number, since it uses as much as digits as its factorization.

10344011213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10344011213 its reverse (31211044301), we get a palindrome (41555055514).

The spelling of 10344011213 in words is "ten billion, three hundred forty-four million, eleven thousand, two hundred thirteen".