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10344013001332 = 222586003250333
BaseRepresentation
bin1001011010000110011100…
…1110000111001001110100
31100121212201001101101222221
42112201213032013021310
52323434014312020312
633555550213332124
72115221166534043
oct226414716071164
940555631341887
1010344013001332
11332896474268a
1211b08a5037044
135a0589560a8a
1427a91d7b855a
1512e11157b207
hex96867387274

10344013001332 has 6 divisors (see below), whose sum is σ = 18102022752338. Its totient is φ = 5172006500664.

The previous prime is 10344013001321. The next prime is 10344013001359. The reversal of 10344013001332 is 23310031044301.

It can be written as a sum of positive squares in only one way, i.e., 10331313063696 + 12699937636 = 3214236^2 + 112694^2 .

It is a junction number, because it is equal to n+sod(n) for n = 10344013001297 and 10344013001306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1293001625163 + ... + 1293001625170.

Almost surely, 210344013001332 is an apocalyptic number.

It is an amenable number.

10344013001332 is a deficient number, since it is larger than the sum of its proper divisors (7758009751006).

10344013001332 is a wasteful number, since it uses less digits than its factorization.

10344013001332 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2586003250337 (or 2586003250335 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10344013001332 its reverse (23310031044301), we get a palindrome (33654044045633).

The spelling of 10344013001332 in words is "ten trillion, three hundred forty-four billion, thirteen million, one thousand, three hundred thirty-two".

Divisors: 1 2 4 2586003250333 5172006500666 10344013001332