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103441321307 is a prime number
BaseRepresentation
bin110000001010110010…
…1010100110101011011
3100220000000002120121102
41200111211110311123
53143321434240212
6115304214302015
710321241503142
oct1402545246533
9326000076542
10103441321307
113a961a247a5
121806a35790b
1399a677263c
145014106759
152a564055c2
hex1815954d5b

103441321307 has 2 divisors, whose sum is σ = 103441321308. Its totient is φ = 103441321306.

The previous prime is 103441321301. The next prime is 103441321309. The reversal of 103441321307 is 703123144301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103441321307 - 212 = 103441317211 is a prime.

Together with 103441321309, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 103441321307.

It is not a weakly prime, because it can be changed into another prime (103441321301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51720660653 + 51720660654.

It is an arithmetic number, because the mean of its divisors is an integer number (51720660654).

Almost surely, 2103441321307 is an apocalyptic number.

103441321307 is a deficient number, since it is larger than the sum of its proper divisors (1).

103441321307 is an equidigital number, since it uses as much as digits as its factorization.

103441321307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 103441321307 its reverse (703123144301), we get a palindrome (806564465608).

The spelling of 103441321307 in words is "one hundred three billion, four hundred forty-one million, three hundred twenty-one thousand, three hundred seven".