Base | Representation |
---|---|
bin | 110000001010111000… |
… | …0000010100100100111 |
3 | 100220000012101021112022 |
4 | 1200111300002210213 |
5 | 3143323144130322 |
6 | 115304354413355 |
7 | 10321304412044 |
oct | 1402560024447 |
9 | 326005337468 |
10 | 103444130087 |
11 | 3a963573001 |
12 | 1806b29125b |
13 | 99a7216c3c |
14 | 50146381cb |
15 | 2a567ac942 |
hex | 1815c02927 |
103444130087 has 2 divisors, whose sum is σ = 103444130088. Its totient is φ = 103444130086.
The previous prime is 103444129939. The next prime is 103444130189. The reversal of 103444130087 is 780031444301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103444130087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103444130287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51722065043 + 51722065044.
It is an arithmetic number, because the mean of its divisors is an integer number (51722065044).
Almost surely, 2103444130087 is an apocalyptic number.
103444130087 is a deficient number, since it is larger than the sum of its proper divisors (1).
103444130087 is an equidigital number, since it uses as much as digits as its factorization.
103444130087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 103444130087 its reverse (780031444301), we get a palindrome (883475574388).
The spelling of 103444130087 in words is "one hundred three billion, four hundred forty-four million, one hundred thirty thousand, eighty-seven".
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