1035132433 has 2 divisors, whose sum is σ = 1035132434. Its totient is φ = 1035132432.

The previous prime is 1035132419. The next prime is 1035132463. The reversal of 1035132433 is 3342315301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 984892689 + 50239744 = 31383^2 + 7088^2 .

It is a cyclic number.

It is not a de Polignac number, because 1035132433 - 2⁵ = 1035132401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1035132398 and 1035132407.

It is not a weakly prime, because it can be changed into another prime (1035132463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517566216 + 517566217.

It is an arithmetic number, because the mean of its divisors is an integer number (517566217).

Almost surely, 2^1035132433 is an apocalyptic number.

It is an amenable number.

1035132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1035132433 is an equidigital number, since it uses as much as digits as its factorization.

1035132433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 1035132433 is about 32173.4740586092. The cubic root of 1035132433 is about 1011.5762835454.

Adding to 1035132433 its reverse (3342315301), we get a palindrome (4377447734).

The spelling of 1035132433 in words is "one billion, thirty-five million, one hundred thirty-two thousand, four hundred thirty-three".