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10354130651659 is a prime number
BaseRepresentation
bin1001011010101100001001…
…0001111000101000001011
31100122211211011112022000211
42112223002101320220023
52324120224421323114
634004342201541551
72116030003252624
oct226530221705013
940584734468024
1010354130651659
113332186904073
1211b28494a48b7
135a150c731812
1427b1dd404a4b
1512e5049286c4
hex96ac2478a0b

10354130651659 has 2 divisors, whose sum is σ = 10354130651660. Its totient is φ = 10354130651658.

The previous prime is 10354130651597. The next prime is 10354130651693. The reversal of 10354130651659 is 95615603145301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10354130651659 - 219 = 10354130127371 is a prime.

It is a super-3 number, since 3×103541306516593 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10354130661659) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177065325829 + 5177065325830.

It is an arithmetic number, because the mean of its divisors is an integer number (5177065325830).

Almost surely, 210354130651659 is an apocalyptic number.

10354130651659 is a deficient number, since it is larger than the sum of its proper divisors (1).

10354130651659 is an equidigital number, since it uses as much as digits as its factorization.

10354130651659 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1458000, while the sum is 49.

The spelling of 10354130651659 in words is "ten trillion, three hundred fifty-four billion, one hundred thirty million, six hundred fifty-one thousand, six hundred fifty-nine".