Search a number
-
+
10354130651693 is a prime number
BaseRepresentation
bin1001011010101100001001…
…0001111000101000101101
31100122211211011112022002002
42112223002101320220231
52324120224421323233
634004342201542045
72116030003253003
oct226530221705055
940584734468062
1010354130651693
1133321869040a4
1211b28494a4925
135a150c73183a
1427b1dd404a73
1512e5049286e8
hex96ac2478a2d

10354130651693 has 2 divisors, whose sum is σ = 10354130651694. Its totient is φ = 10354130651692.

The previous prime is 10354130651659. The next prime is 10354130651723. The reversal of 10354130651693 is 39615603145301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9884723424004 + 469407227689 = 3143998^2 + 685133^2 .

It is a cyclic number.

It is not a de Polignac number, because 10354130651693 - 28 = 10354130651437 is a prime.

It is a super-3 number, since 3×103541306516933 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10354130651593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177065325846 + 5177065325847.

It is an arithmetic number, because the mean of its divisors is an integer number (5177065325847).

Almost surely, 210354130651693 is an apocalyptic number.

It is an amenable number.

10354130651693 is a deficient number, since it is larger than the sum of its proper divisors (1).

10354130651693 is an equidigital number, since it uses as much as digits as its factorization.

10354130651693 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 874800, while the sum is 47.

Adding to 10354130651693 its reverse (39615603145301), we get a palindrome (49969733796994).

The spelling of 10354130651693 in words is "ten trillion, three hundred fifty-four billion, one hundred thirty million, six hundred fifty-one thousand, six hundred ninety-three".