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103542275215013 is a prime number
BaseRepresentation
bin10111100010101111010000…
…100010001000111010100101
3111120121112201012001221201112
4113202233100202020322211
5102032414034423340023
61004114355314034405
730544453050522515
oct2742572042107245
9446545635057645
10103542275215013
112aaa003a021078
12b74322a578a05
1345a0cc1350c2b
141b7d689755845
15be858b256478
hex5e2bd0888ea5

103542275215013 has 2 divisors, whose sum is σ = 103542275215014. Its totient is φ = 103542275215012.

The previous prime is 103542275214967. The next prime is 103542275215097. The reversal of 103542275215013 is 310512572245301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94261710069409 + 9280565145604 = 9708847^2 + 3046402^2 .

It is a cyclic number.

It is not a de Polignac number, because 103542275215013 - 212 = 103542275210917 is a prime.

It is a super-3 number, since 3×1035422752150133 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103542275715013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51771137607506 + 51771137607507.

It is an arithmetic number, because the mean of its divisors is an integer number (51771137607507).

Almost surely, 2103542275215013 is an apocalyptic number.

It is an amenable number.

103542275215013 is a deficient number, since it is larger than the sum of its proper divisors (1).

103542275215013 is an equidigital number, since it uses as much as digits as its factorization.

103542275215013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 41.

The spelling of 103542275215013 in words is "one hundred three trillion, five hundred forty-two billion, two hundred seventy-five million, two hundred fifteen thousand, thirteen".