Base | Representation |
---|---|
bin | 110000001101110100… |
… | …1111101111001110001 |
3 | 100220021002210121210221 |
4 | 1200123221331321301 |
5 | 3144024024421033 |
6 | 115322254053041 |
7 | 10323616455502 |
oct | 1403351757161 |
9 | 326232717727 |
10 | 103543201393 |
11 | 3aa0448a815 |
12 | 180984aa181 |
13 | 99c18c3b08 |
14 | 5023866ba9 |
15 | 2a6032c12d |
hex | 181ba7de71 |
103543201393 has 2 divisors, whose sum is σ = 103543201394. Its totient is φ = 103543201392.
The previous prime is 103543201369. The next prime is 103543201453. The reversal of 103543201393 is 393102345301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102711917169 + 831284224 = 320487^2 + 28832^2 .
It is a cyclic number.
It is not a de Polignac number, because 103543201393 - 29 = 103543200881 is a prime.
It is a super-3 number, since 3×1035432013933 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (103543201693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51771600696 + 51771600697.
It is an arithmetic number, because the mean of its divisors is an integer number (51771600697).
Almost surely, 2103543201393 is an apocalyptic number.
It is an amenable number.
103543201393 is a deficient number, since it is larger than the sum of its proper divisors (1).
103543201393 is an equidigital number, since it uses as much as digits as its factorization.
103543201393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29160, while the sum is 34.
Adding to 103543201393 its reverse (393102345301), we get a palindrome (496645546694).
The spelling of 103543201393 in words is "one hundred three billion, five hundred forty-three million, two hundred one thousand, three hundred ninety-three".
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