103543201425 has 12 divisors (see below), whose sum is σ = 171191426480. Its totient is φ = 55223040720.

The previous prime is 103543201393. The next prime is 103543201453. The reversal of 103543201425 is 524102345301.

It is not a de Polignac number, because 103543201425 - 2⁵ = 103543201393 is a prime.

It is a super-3 number, since 3×103543201425³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 103543201392 and 103543201401.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 690287935 + ... + 690288084.

Almost surely, 2^103543201425 is an apocalyptic number.

103543201425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

103543201425 is a deficient number, since it is larger than the sum of its proper divisors (67648225055).

103543201425 is a wasteful number, since it uses less digits than its factorization.

103543201425 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1380576032 (or 1380576027 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 30.

Adding to 103543201425 its reverse (524102345301), we get a palindrome (627645546726).

The spelling of 103543201425 in words is "one hundred three billion, five hundred forty-three million, two hundred one thousand, four hundred twenty-five".