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10355214613 is a prime number
BaseRepresentation
bin10011010010011100…
…00000100100010101
3222201200011101222011
421221032000210111
5132201413331423
64431312104221
7514416605032
oct115116004425
928650141864
1010355214613
114434281007
12200bb35071
13c9047b033
147033ca389
15409176b0d
hex269380915

10355214613 has 2 divisors, whose sum is σ = 10355214614. Its totient is φ = 10355214612.

The previous prime is 10355214593. The next prime is 10355214659. The reversal of 10355214613 is 31641255301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8127563409 + 2227651204 = 90153^2 + 47198^2 .

It is a cyclic number.

It is not a de Polignac number, because 10355214613 - 25 = 10355214581 is a prime.

It is a super-3 number, since 3×103552146133 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10355214713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177607306 + 5177607307.

It is an arithmetic number, because the mean of its divisors is an integer number (5177607307).

Almost surely, 210355214613 is an apocalyptic number.

It is an amenable number.

10355214613 is a deficient number, since it is larger than the sum of its proper divisors (1).

10355214613 is an equidigital number, since it uses as much as digits as its factorization.

10355214613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 10355214613 its reverse (31641255301), we get a palindrome (41996469914).

The spelling of 10355214613 in words is "ten billion, three hundred fifty-five million, two hundred fourteen thousand, six hundred thirteen".