Base | Representation |
---|---|
bin | 1001011010110011010011… |
… | …1111100111001010000111 |
3 | 1100200000210021222120202112 |
4 | 2112230310333213022013 |
5 | 2324133200120210401 |
6 | 34005301152331235 |
7 | 2116125463065401 |
oct | 226546477471207 |
9 | 40600707876675 |
10 | 10356055241351 |
11 | 3332a84224866 |
12 | 11b30a5b43b1b |
13 | 5a17583948a1 |
14 | 27b342c6db71 |
15 | 12e5b88923bb |
hex | 96b34fe7287 |
10356055241351 has 2 divisors, whose sum is σ = 10356055241352. Its totient is φ = 10356055241350.
The previous prime is 10356055241333. The next prime is 10356055241449. The reversal of 10356055241351 is 15314255065301.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10356055241351 is a prime.
It is a super-3 number, since 3×103560552413513 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10356055241299 and 10356055241308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10356055240351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5178027620675 + 5178027620676.
It is an arithmetic number, because the mean of its divisors is an integer number (5178027620676).
Almost surely, 210356055241351 is an apocalyptic number.
10356055241351 is a deficient number, since it is larger than the sum of its proper divisors (1).
10356055241351 is an equidigital number, since it uses as much as digits as its factorization.
10356055241351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 270000, while the sum is 41.
The spelling of 10356055241351 in words is "ten trillion, three hundred fifty-six billion, fifty-five million, two hundred forty-one thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •