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10356055241351 is a prime number
BaseRepresentation
bin1001011010110011010011…
…1111100111001010000111
31100200000210021222120202112
42112230310333213022013
52324133200120210401
634005301152331235
72116125463065401
oct226546477471207
940600707876675
1010356055241351
113332a84224866
1211b30a5b43b1b
135a17583948a1
1427b342c6db71
1512e5b88923bb
hex96b34fe7287

10356055241351 has 2 divisors, whose sum is σ = 10356055241352. Its totient is φ = 10356055241350.

The previous prime is 10356055241333. The next prime is 10356055241449. The reversal of 10356055241351 is 15314255065301.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10356055241351 is a prime.

It is a super-3 number, since 3×103560552413513 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10356055241299 and 10356055241308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10356055240351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5178027620675 + 5178027620676.

It is an arithmetic number, because the mean of its divisors is an integer number (5178027620676).

Almost surely, 210356055241351 is an apocalyptic number.

10356055241351 is a deficient number, since it is larger than the sum of its proper divisors (1).

10356055241351 is an equidigital number, since it uses as much as digits as its factorization.

10356055241351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270000, while the sum is 41.

The spelling of 10356055241351 in words is "ten trillion, three hundred fifty-six billion, fifty-five million, two hundred forty-one thousand, three hundred fifty-one".