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10363874341813 is a prime number
BaseRepresentation
bin1001011011010000011100…
…0011000111001110110101
31100200202222020000001010221
42112310013003013032311
52324300203312414223
634013033111014341
72116523316252556
oct226640703071665
940622866001127
1010363874341813
113336326975763
1211b470866a3b1
135a24032aa555
1427b8854c832d
1512e8c5057b5d
hex96d070c73b5

10363874341813 has 2 divisors, whose sum is σ = 10363874341814. Its totient is φ = 10363874341812.

The previous prime is 10363874341783. The next prime is 10363874341829. The reversal of 10363874341813 is 31814347836301.

10363874341813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10359688510609 + 4185831204 = 3218647^2 + 64698^2 .

It is a cyclic number.

It is not a de Polignac number, because 10363874341813 - 25 = 10363874341781 is a prime.

It is a super-3 number, since 3×103638743418133 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10363874341853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5181937170906 + 5181937170907.

It is an arithmetic number, because the mean of its divisors is an integer number (5181937170907).

Almost surely, 210363874341813 is an apocalyptic number.

It is an amenable number.

10363874341813 is a deficient number, since it is larger than the sum of its proper divisors (1).

10363874341813 is an equidigital number, since it uses as much as digits as its factorization.

10363874341813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3483648, while the sum is 52.

The spelling of 10363874341813 in words is "ten trillion, three hundred sixty-three billion, eight hundred seventy-four million, three hundred forty-one thousand, eight hundred thirteen".