1038327104051 has 2 divisors, whose sum is σ = 1038327104052. Its totient is φ = 1038327104050.

The previous prime is 1038327104033. The next prime is 1038327104053. The reversal of 1038327104051 is 1504017238301.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1038327104051 is a prime.

It is a super-3 number, since 3×1038327104051³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1038327104053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1038327104053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 519163552025 + 519163552026.

It is an arithmetic number, because the mean of its divisors is an integer number (519163552026).

Almost surely, 2^{1038327104051} is an apocalyptic number.

1038327104051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1038327104051 is an equidigital number, since it uses as much as digits as its factorization.

1038327104051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 35.

The spelling of 1038327104051 in words is "one trillion, thirty-eight billion, three hundred twenty-seven million, one hundred four thousand, fifty-one".