Base | Representation |
---|---|
bin | 10111101001011010111000… |
… | …010111101110111000000111 |
3 | 111122020102212120022112220022 |
4 | 113221122320113232320013 |
5 | 102112424412410200112 |
6 | 1005105333055125355 |
7 | 30622566264245105 |
oct | 2751327027567007 |
9 | 448212776275808 |
10 | 104001431334407 |
11 | 30157839749542 |
12 | b7b8210b1385b |
13 | 46053a66415c9 |
14 | 1b979a629cc75 |
15 | c054b125dd72 |
hex | 5e96b85eee07 |
104001431334407 has 2 divisors, whose sum is σ = 104001431334408. Its totient is φ = 104001431334406.
The previous prime is 104001431334389. The next prime is 104001431334469. The reversal of 104001431334407 is 704433134100401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104001431334407 - 214 = 104001431318023 is a prime.
It is a super-3 number, since 3×1040014313344073 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104001431334707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52000715667203 + 52000715667204.
It is an arithmetic number, because the mean of its divisors is an integer number (52000715667204).
Almost surely, 2104001431334407 is an apocalyptic number.
104001431334407 is a deficient number, since it is larger than the sum of its proper divisors (1).
104001431334407 is an equidigital number, since it uses as much as digits as its factorization.
104001431334407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 104001431334407 its reverse (704433134100401), we get a palindrome (808434565434808).
The spelling of 104001431334407 in words is "one hundred four trillion, one billion, four hundred thirty-one million, three hundred thirty-four thousand, four hundred seven".
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