1040113121 has 2 divisors, whose sum is σ = 1040113122. Its totient is φ = 1040113120.

The previous prime is 1040113099. The next prime is 1040113157. The reversal of 1040113121 is 1213110401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1019908096 + 20205025 = 31936^2 + 4495^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1040113121 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1040113096 and 1040113105.

It is not a weakly prime, because it can be changed into another prime (1040113021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520056560 + 520056561.

It is an arithmetic number, because the mean of its divisors is an integer number (520056561).

Almost surely, 2^1040113121 is an apocalyptic number.

It is an amenable number.

1040113121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040113121 is an equidigital number, since it uses as much as digits as its factorization.

1040113121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 1040113121 is about 32250.7848121561. The cubic root of 1040113121 is about 1013.1961363361.

Adding to 1040113121 its reverse (1213110401), we get a palindrome (2253223522).

The spelling of 1040113121 in words is "one billion, forty million, one hundred thirteen thousand, one hundred twenty-one".