104011331 has 2 divisors, whose sum is σ = 104011332. Its totient is φ = 104011330.

The previous prime is 104011309. The next prime is 104011333. The reversal of 104011331 is 133110401.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-104011331 is a prime.

It is a super-3 number, since 3×104011331³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 104011333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104011333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52005665 + 52005666.

It is an arithmetic number, because the mean of its divisors is an integer number (52005666).

Almost surely, 2^104011331 is an apocalyptic number.

104011331 is a deficient number, since it is larger than the sum of its proper divisors (1).

104011331 is an equidigital number, since it uses as much as digits as its factorization.

104011331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 104011331 is about 10198.5945600362. The cubic root of 104011331 is about 470.2840157530.

Adding to 104011331 its reverse (133110401), we get a palindrome (237121732).

The spelling of 104011331 in words is "one hundred four million, eleven thousand, three hundred thirty-one".