10401243311 has 2 divisors, whose sum is σ = 10401243312. Its totient is φ = 10401243310.

The previous prime is 10401243299. The next prime is 10401243337. The reversal of 10401243311 is 11334210401.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10401243311 is a prime.

It is a super-3 number, since 3×10401243311³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10401243341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200621655 + 5200621656.

It is an arithmetic number, because the mean of its divisors is an integer number (5200621656).

Almost surely, 2^10401243311 is an apocalyptic number.

10401243311 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401243311 is an equidigital number, since it uses as much as digits as its factorization.

10401243311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10401243311 its reverse (11334210401), we get a palindrome (21735453712).

The spelling of 10401243311 in words is "ten billion, four hundred one million, two hundred forty-three thousand, three hundred eleven".