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104012537 is a prime number
BaseRepresentation
bin1100011001100…
…01101011111001
321020201101101012
412030301223321
5203111400122
614153203305
72402043356
oct614615371
9236641335
10104012537
1153792182
122aa00535
1318719ca5
14db5762d
1591e87e2
hex6331af9

104012537 has 2 divisors, whose sum is σ = 104012538. Its totient is φ = 104012536.

The previous prime is 104012507. The next prime is 104012567. The reversal of 104012537 is 735210401.

It is a balanced prime because it is at equal distance from previous prime (104012507) and next prime (104012567).

It can be written as a sum of positive squares in only one way, i.e., 61293241 + 42719296 = 7829^2 + 6536^2 .

It is a cyclic number.

It is not a de Polignac number, because 104012537 - 220 = 102963961 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104012507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52006268 + 52006269.

It is an arithmetic number, because the mean of its divisors is an integer number (52006269).

Almost surely, 2104012537 is an apocalyptic number.

It is an amenable number.

104012537 is a deficient number, since it is larger than the sum of its proper divisors (1).

104012537 is an equidigital number, since it uses as much as digits as its factorization.

104012537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 104012537 is about 10198.6536856587. The cubic root of 104012537 is about 470.2858333765.

Adding to 104012537 its reverse (735210401), we get a palindrome (839222938).

The spelling of 104012537 in words is "one hundred four million, twelve thousand, five hundred thirty-seven".