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104013137 is a prime number
BaseRepresentation
bin1100011001100…
…01110101010001
321020201102012102
412030301311101
5203111410022
614153210145
72402045204
oct614616521
9236642172
10104013137
1153792678
122aa00955
131871a347
14db5793b
1591e8a92
hex6331d51

104013137 has 2 divisors, whose sum is σ = 104013138. Its totient is φ = 104013136.

The previous prime is 104013131. The next prime is 104013149. The reversal of 104013137 is 731310401.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102738496 + 1274641 = 10136^2 + 1129^2 .

It is a cyclic number.

It is not a de Polignac number, because 104013137 - 26 = 104013073 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104013131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52006568 + 52006569.

It is an arithmetic number, because the mean of its divisors is an integer number (52006569).

Almost surely, 2104013137 is an apocalyptic number.

It is an amenable number.

104013137 is a deficient number, since it is larger than the sum of its proper divisors (1).

104013137 is an equidigital number, since it uses as much as digits as its factorization.

104013137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

The square root of 104013137 is about 10198.6831012636. The cubic root of 104013137 is about 470.2867376616.

Adding to 104013137 its reverse (731310401), we get a palindrome (835323538).

The spelling of 104013137 in words is "one hundred four million, thirteen thousand, one hundred thirty-seven".