104013151241 has 2 divisors, whose sum is σ = 104013151242. Its totient is φ = 104013151240.

The previous prime is 104013151219. The next prime is 104013151243. The reversal of 104013151241 is 142151310401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81222720016 + 22790431225 = 284996^2 + 150965^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-104013151241 is a prime.

Together with 104013151243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104013151243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52006575620 + 52006575621.

It is an arithmetic number, because the mean of its divisors is an integer number (52006575621).

Almost surely, 2^104013151241 is an apocalyptic number.

It is an amenable number.

104013151241 is a deficient number, since it is larger than the sum of its proper divisors (1).

104013151241 is an equidigital number, since it uses as much as digits as its factorization.

104013151241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 104013151241 its reverse (142151310401), we get a palindrome (246164461642).

The spelling of 104013151241 in words is "one hundred four billion, thirteen million, one hundred fifty-one thousand, two hundred forty-one".