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10401331121897 is a prime number
BaseRepresentation
bin1001011101011011111110…
…1001011000111011101001
31100211100122122112121210012
42113112333221120323221
52330403411231400042
634042145555501305
72122320452526212
oct227267751307351
940740578477705
1010401331121897
1133501a828aa61
1211bba208b7835
135a5ac24aa351
1427d5d9dd4409
15130868627e82
hex975bfa58ee9

10401331121897 has 2 divisors, whose sum is σ = 10401331121898. Its totient is φ = 10401331121896.

The previous prime is 10401331121891. The next prime is 10401331121899. The reversal of 10401331121897 is 79812113310401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7897021706896 + 2504309415001 = 2810164^2 + 1582501^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10401331121897 is a prime.

Together with 10401331121899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10401331121891) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200665560948 + 5200665560949.

It is an arithmetic number, because the mean of its divisors is an integer number (5200665560949).

Almost surely, 210401331121897 is an apocalyptic number.

It is an amenable number.

10401331121897 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401331121897 is an equidigital number, since it uses as much as digits as its factorization.

10401331121897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 41.

The spelling of 10401331121897 in words is "ten trillion, four hundred one billion, three hundred thirty-one million, one hundred twenty-one thousand, eight hundred ninety-seven".