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10401382811 is a prime number
BaseRepresentation
bin10011010111111100…
…01000000110011011
3222211220000222211102
421223332020012123
5132300223222221
64440041422015
7515520203141
oct115376100633
928756028742
1010401382811
114458344946
12202349a90b
13c99bc42b1
147095a7591
1540d24630b
hex26bf8819b

10401382811 has 2 divisors, whose sum is σ = 10401382812. Its totient is φ = 10401382810.

The previous prime is 10401382793. The next prime is 10401382813. The reversal of 10401382811 is 11828310401.

It is a strong prime.

It is an emirp because it is prime and its reverse (11828310401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10401382811 - 210 = 10401381787 is a prime.

Together with 10401382813, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10401382813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200691405 + 5200691406.

It is an arithmetic number, because the mean of its divisors is an integer number (5200691406).

Almost surely, 210401382811 is an apocalyptic number.

10401382811 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401382811 is an equidigital number, since it uses as much as digits as its factorization.

10401382811 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 29.

The spelling of 10401382811 in words is "ten billion, four hundred one million, three hundred eighty-two thousand, eight hundred eleven".