Base | Representation |
---|---|
bin | 11110010001011010011… |
… | …00110100100001101111 |
3 | 10200102210011201002200212 |
4 | 33020231030310201233 |
5 | 114020201421434411 |
6 | 2113500043013035 |
7 | 135101435463122 |
oct | 17105514644157 |
9 | 3612704632625 |
10 | 1040140421231 |
11 | 37113717353a |
12 | 149704b0a17b |
13 | 77114475092 |
14 | 384b35283b9 |
15 | 1c0ca73968b |
hex | f22d33486f |
1040140421231 has 2 divisors, whose sum is σ = 1040140421232. Its totient is φ = 1040140421230.
The previous prime is 1040140421227. The next prime is 1040140421261. The reversal of 1040140421231 is 1321240410401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1040140421231 - 22 = 1040140421227 is a prime.
It is a super-2 number, since 2×10401404212312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1040140421197 and 1040140421206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1040140421261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520070210615 + 520070210616.
It is an arithmetic number, because the mean of its divisors is an integer number (520070210616).
Almost surely, 21040140421231 is an apocalyptic number.
1040140421231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1040140421231 is an equidigital number, since it uses as much as digits as its factorization.
1040140421231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1040140421231 its reverse (1321240410401), we get a palindrome (2361380831632).
The spelling of 1040140421231 in words is "one trillion, forty billion, one hundred forty million, four hundred twenty-one thousand, two hundred thirty-one".
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