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1040151283 is a prime number
BaseRepresentation
bin111101111111110…
…111001011110011
32200111020011022121
4331333313023303
54112234320113
6251114015111
734530066013
oct7577671363
92614204277
101040151283
11494158066
12250417497
13137657842
149c1ddc43
15614b2e8d
hex3dff72f3

1040151283 has 2 divisors, whose sum is σ = 1040151284. Its totient is φ = 1040151282.

The previous prime is 1040151253. The next prime is 1040151311. The reversal of 1040151283 is 3821510401.

It is a strong prime.

It is an emirp because it is prime and its reverse (3821510401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1040151283 - 25 = 1040151251 is a prime.

It is not a weakly prime, because it can be changed into another prime (1040151253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520075641 + 520075642.

It is an arithmetic number, because the mean of its divisors is an integer number (520075642).

Almost surely, 21040151283 is an apocalyptic number.

1040151283 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040151283 is an equidigital number, since it uses as much as digits as its factorization.

1040151283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

The square root of 1040151283 is about 32251.3764512462. The cubic root of 1040151283 is about 1013.2085276544.

Adding to 1040151283 its reverse (3821510401), we get a palindrome (4861661684).

The spelling of 1040151283 in words is "one billion, forty million, one hundred fifty-one thousand, two hundred eighty-three".