Base | Representation |
---|---|
bin | 1001011101011110010101… |
… | …1100101011001101101101 |
3 | 1100211102021211220101022021 |
4 | 2113113211130223031231 |
5 | 2330411211110314432 |
6 | 34042332532550141 |
7 | 2122342253252314 |
oct | 227274534531555 |
9 | 40742254811267 |
10 | 10401965323117 |
11 | 33504a32787a5 |
12 | 11bbb79182351 |
13 | 5a5b939bc244 |
14 | 27d65a32127b |
15 | 1308a414e697 |
hex | 975e572b36d |
10401965323117 has 2 divisors, whose sum is σ = 10401965323118. Its totient is φ = 10401965323116.
The previous prime is 10401965323103. The next prime is 10401965323187. The reversal of 10401965323117 is 71132356910401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6457971892516 + 3943993430601 = 2541254^2 + 1985949^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10401965323117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10401965323187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200982661558 + 5200982661559.
It is an arithmetic number, because the mean of its divisors is an integer number (5200982661559).
Almost surely, 210401965323117 is an apocalyptic number.
It is an amenable number.
10401965323117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10401965323117 is an equidigital number, since it uses as much as digits as its factorization.
10401965323117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 10401965323117 in words is "ten trillion, four hundred one billion, nine hundred sixty-five million, three hundred twenty-three thousand, one hundred seventeen".
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