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10402013122133 is a prime number
BaseRepresentation
bin1001011101011110100001…
…0011000000111001010101
31100211102102011211211020012
42113113220103000321111
52330411310324402013
634042341401250005
72122343403452123
oct227275023007125
940742364754205
1010402013122133
113350518255916
1211bbb91193905
135a5ba0886899
1427d662804913
151308a84421a8
hex975e84c0e55

10402013122133 has 2 divisors, whose sum is σ = 10402013122134. Its totient is φ = 10402013122132.

The previous prime is 10402013122099. The next prime is 10402013122147. The reversal of 10402013122133 is 33122131020401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8647492998244 + 1754520123889 = 2940662^2 + 1324583^2 .

It is a cyclic number.

It is not a de Polignac number, because 10402013122133 - 216 = 10402013056597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10402013122099 and 10402013122108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10402013121133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5201006561066 + 5201006561067.

It is an arithmetic number, because the mean of its divisors is an integer number (5201006561067).

Almost surely, 210402013122133 is an apocalyptic number.

It is an amenable number.

10402013122133 is a deficient number, since it is larger than the sum of its proper divisors (1).

10402013122133 is an equidigital number, since it uses as much as digits as its factorization.

10402013122133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 10402013122133 its reverse (33122131020401), we get a palindrome (43524144142534).

The spelling of 10402013122133 in words is "ten trillion, four hundred two billion, thirteen million, one hundred twenty-two thousand, one hundred thirty-three".