Base | Representation |
---|---|
bin | 1001011101011110100011… |
… | …1101000000111000001111 |
3 | 1100211102102221120012002011 |
4 | 2113113220331000320033 |
5 | 2330411321134211421 |
6 | 34042342433242051 |
7 | 2122343566156153 |
oct | 227275075007017 |
9 | 40742387505064 |
10 | 10402024132111 |
11 | 3350523495877 |
12 | 11bbb94a03327 |
13 | 5a5ba2c40071 |
14 | 27d66406d063 |
15 | 1308a93b94e1 |
hex | 975e8f40e0f |
10402024132111 has 2 divisors, whose sum is σ = 10402024132112. Its totient is φ = 10402024132110.
The previous prime is 10402024132079. The next prime is 10402024132117. The reversal of 10402024132111 is 11123142020401.
It is a strong prime.
It is an emirp because it is prime and its reverse (11123142020401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10402024132111 - 25 = 10402024132079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10402024132117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5201012066055 + 5201012066056.
It is an arithmetic number, because the mean of its divisors is an integer number (5201012066056).
Almost surely, 210402024132111 is an apocalyptic number.
10402024132111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10402024132111 is an equidigital number, since it uses as much as digits as its factorization.
10402024132111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 10402024132111 its reverse (11123142020401), we get a palindrome (21525166152512).
The spelling of 10402024132111 in words is "ten trillion, four hundred two billion, twenty-four million, one hundred thirty-two thousand, one hundred eleven".
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