Base | Representation |
---|---|
bin | 10111101001101101011011… |
… | …001101001001000001111101 |
3 | 111122022100021020211201121011 |
4 | 113221231123031021001331 |
5 | 102113241202314111331 |
6 | 1005122424553435221 |
7 | 30624202565465533 |
oct | 2751553315110175 |
9 | 448270236751534 |
10 | 104021343113341 |
11 | 301652273a1795 |
12 | b80004940bb11 |
13 | 460722a96ac14 |
14 | 1b9893497c153 |
15 | c05c793a03b1 |
hex | 5e9b5b34907d |
104021343113341 has 2 divisors, whose sum is σ = 104021343113342. Its totient is φ = 104021343113340.
The previous prime is 104021343113329. The next prime is 104021343113383. The reversal of 104021343113341 is 143311343120401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60324021057316 + 43697322056025 = 7766854^2 + 6610395^2 .
It is a cyclic number.
It is not a de Polignac number, because 104021343113341 - 27 = 104021343113213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104021343113041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52010671556670 + 52010671556671.
It is an arithmetic number, because the mean of its divisors is an integer number (52010671556671).
Almost surely, 2104021343113341 is an apocalyptic number.
It is an amenable number.
104021343113341 is a deficient number, since it is larger than the sum of its proper divisors (1).
104021343113341 is an equidigital number, since it uses as much as digits as its factorization.
104021343113341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 104021343113341 its reverse (143311343120401), we get a palindrome (247332686233742).
The spelling of 104021343113341 in words is "one hundred four trillion, twenty-one billion, three hundred forty-three million, one hundred thirteen thousand, three hundred forty-one".
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