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1040250555413 is a prime number
BaseRepresentation
bin11110010001100111100…
…00111100110000010101
310200110001211221111101122
433020303300330300111
5114020413120233123
62113515015333325
7135104243554046
oct17106360746025
93613054844348
101040250555413
11371193356a23
12149735981245
1377131226534
14384c3dd68cd
151c0d5241bc8
hexf233c3cc15

1040250555413 has 2 divisors, whose sum is σ = 1040250555414. Its totient is φ = 1040250555412.

The previous prime is 1040250555367. The next prime is 1040250555433. The reversal of 1040250555413 is 3145550520401.

1040250555413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1037664120964 + 2586434449 = 1018658^2 + 50857^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1040250555413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1040250555433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520125277706 + 520125277707.

It is an arithmetic number, because the mean of its divisors is an integer number (520125277707).

Almost surely, 21040250555413 is an apocalyptic number.

It is an amenable number.

1040250555413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040250555413 is an equidigital number, since it uses as much as digits as its factorization.

1040250555413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60000, while the sum is 35.

The spelling of 1040250555413 in words is "one trillion, forty billion, two hundred fifty million, five hundred fifty-five thousand, four hundred thirteen".