Base | Representation |
---|---|
bin | 110000011100111011… |
… | …0010100010001000011 |
3 | 100221120101222020000011 |
4 | 1200321312110101003 |
5 | 3201043214131303 |
6 | 115444431205351 |
7 | 10342310216662 |
oct | 1407166242103 |
9 | 327511866004 |
10 | 104049755203 |
11 | 40144413129 |
12 | 181ba076857 |
13 | 9a72831cb4 |
14 | 5070c46dd9 |
15 | 2a8ea3c16d |
hex | 1839d94443 |
104049755203 has 2 divisors, whose sum is σ = 104049755204. Its totient is φ = 104049755202.
The previous prime is 104049755179. The next prime is 104049755287. The reversal of 104049755203 is 302557940401.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104049755203 - 25 = 104049755171 is a prime.
It is not a weakly prime, because it can be changed into another prime (104049765203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52024877601 + 52024877602.
It is an arithmetic number, because the mean of its divisors is an integer number (52024877602).
Almost surely, 2104049755203 is an apocalyptic number.
104049755203 is a deficient number, since it is larger than the sum of its proper divisors (1).
104049755203 is an equidigital number, since it uses as much as digits as its factorization.
104049755203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 104049755203 in words is "one hundred four billion, forty-nine million, seven hundred fifty-five thousand, two hundred three".
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