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1041045252281 is a prime number
BaseRepresentation
bin11110010011000110010…
…00011110100010111001
310200112010020022021112222
433021203020132202321
5114024030041033111
62114125524413425
7135133033432406
oct17114310364271
93615106267488
101041045252281
113715609a54a1
12149917b47275
1377229a70678
143855b7812ad
151c12edbc7db
hexf26321e8b9

1041045252281 has 2 divisors, whose sum is σ = 1041045252282. Its totient is φ = 1041045252280.

The previous prime is 1041045252209. The next prime is 1041045252283. The reversal of 1041045252281 is 1822525401401.

1041045252281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 948714960400 + 92330291881 = 974020^2 + 303859^2 .

It is a cyclic number.

It is not a de Polignac number, because 1041045252281 - 218 = 1041044990137 is a prime.

It is a super-2 number, since 2×10410452522812 (a number of 25 digits) contains 22 as substring.

Together with 1041045252283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1041045252283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520522626140 + 520522626141.

It is an arithmetic number, because the mean of its divisors is an integer number (520522626141).

Almost surely, 21041045252281 is an apocalyptic number.

It is an amenable number.

1041045252281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041045252281 is an equidigital number, since it uses as much as digits as its factorization.

1041045252281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25600, while the sum is 35.

The spelling of 1041045252281 in words is "one trillion, forty-one billion, forty-five million, two hundred fifty-two thousand, two hundred eighty-one".