Base | Representation |
---|---|
bin | 11110010011001101111… |
… | …11111001010010111001 |
3 | 10200112021202100110120012 |
4 | 33021212333321102321 |
5 | 114024143142031132 |
6 | 2114140202511305 |
7 | 135134451635165 |
oct | 17114677712271 |
9 | 3615252313505 |
10 | 1041110111417 |
11 | 371594575092 |
12 | 149935805535 |
13 | 7723a32c25c |
14 | 38566225ca5 |
15 | 1c1359300b2 |
hex | f266ff94b9 |
1041110111417 has 2 divisors, whose sum is σ = 1041110111418. Its totient is φ = 1041110111416.
The previous prime is 1041110111383. The next prime is 1041110111441. The reversal of 1041110111417 is 7141110111401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 811181230336 + 229928881081 = 900656^2 + 479509^2 .
It is a cyclic number.
It is not a de Polignac number, because 1041110111417 - 214 = 1041110095033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1041110111392 and 1041110111401.
It is not a weakly prime, because it can be changed into another prime (1041110101417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520555055708 + 520555055709.
It is an arithmetic number, because the mean of its divisors is an integer number (520555055709).
Almost surely, 21041110111417 is an apocalyptic number.
It is an amenable number.
1041110111417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041110111417 is an equidigital number, since it uses as much as digits as its factorization.
1041110111417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 23.
Adding to 1041110111417 its reverse (7141110111401), we get a palindrome (8182220222818).
The spelling of 1041110111417 in words is "one trillion, forty-one billion, one hundred ten million, one hundred eleven thousand, four hundred seventeen".
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