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10411242013 is a prime number
BaseRepresentation
bin10011011001000111…
…01111001000011101
3222212120120220010001
421230203233020131
5132310234221023
64441033014301
7516000045154
oct115443571035
928776526101
1010411242013
114462969247
122026854391
13c9bc66a43
1470aa1259b
1540e0426ad
hex26c8ef21d

10411242013 has 2 divisors, whose sum is σ = 10411242014. Its totient is φ = 10411242012.

The previous prime is 10411241999. The next prime is 10411242043. The reversal of 10411242013 is 31024211401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8918346969 + 1492895044 = 94437^2 + 38638^2 .

It is an emirp because it is prime and its reverse (31024211401) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10411242013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10411242043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5205621006 + 5205621007.

It is an arithmetic number, because the mean of its divisors is an integer number (5205621007).

Almost surely, 210411242013 is an apocalyptic number.

It is an amenable number.

10411242013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10411242013 is an equidigital number, since it uses as much as digits as its factorization.

10411242013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 10411242013 its reverse (31024211401), we get a palindrome (41435453414).

The spelling of 10411242013 in words is "ten billion, four hundred eleven million, two hundred forty-two thousand, thirteen".