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10412131440083 is a prime number
BaseRepresentation
bin1001011110000100001101…
…1001010101010111010011
31100212101112100020122001212
42113201003121111113103
52331043021122040313
634051133412050335
72123152215651302
oct227410331252723
940771470218055
1010412131440083
11335483a83295a
121201b359039ab
135a6b23c2c479
1427dd42566439
15130c9b8c23a8
hex978436555d3

10412131440083 has 2 divisors, whose sum is σ = 10412131440084. Its totient is φ = 10412131440082.

The previous prime is 10412131440019. The next prime is 10412131440131. The reversal of 10412131440083 is 38004413121401.

10412131440083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10412131440083 - 26 = 10412131440019 is a prime.

It is a super-2 number, since 2×104121314400832 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10412131440283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206065720041 + 5206065720042.

It is an arithmetic number, because the mean of its divisors is an integer number (5206065720042).

Almost surely, 210412131440083 is an apocalyptic number.

10412131440083 is a deficient number, since it is larger than the sum of its proper divisors (1).

10412131440083 is an equidigital number, since it uses as much as digits as its factorization.

10412131440083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 10412131440083 its reverse (38004413121401), we get a palindrome (48416544561484).

The spelling of 10412131440083 in words is "ten trillion, four hundred twelve billion, one hundred thirty-one million, four hundred forty thousand, eighty-three".