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10412131440371 is a prime number
BaseRepresentation
bin1001011110000100001101…
…1001010101011011110011
31100212101112100020122110112
42113201003121111123303
52331043021122042441
634051133412051535
72123152215652163
oct227410331253363
940771470218415
1010412131440371
11335483a8330a1
121201b35903bab
135a6b23c2c63b
1427dd425665a3
15130c9b8c24eb
hex978436556f3

10412131440371 has 2 divisors, whose sum is σ = 10412131440372. Its totient is φ = 10412131440370.

The previous prime is 10412131440349. The next prime is 10412131440407. The reversal of 10412131440371 is 17304413121401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10412131440371 - 242 = 6014084929267 is a prime.

It is a super-2 number, since 2×104121314403712 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10412131440311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206065720185 + 5206065720186.

It is an arithmetic number, because the mean of its divisors is an integer number (5206065720186).

Almost surely, 210412131440371 is an apocalyptic number.

10412131440371 is a deficient number, since it is larger than the sum of its proper divisors (1).

10412131440371 is an equidigital number, since it uses as much as digits as its factorization.

10412131440371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 32.

Adding to 10412131440371 its reverse (17304413121401), we get a palindrome (27716544561772).

The spelling of 10412131440371 in words is "ten trillion, four hundred twelve billion, one hundred thirty-one million, four hundred forty thousand, three hundred seventy-one".