Base | Representation |
---|---|
bin | 11110010011011100010… |
… | …01010010001100011011 |
3 | 10200112121002222002220101 |
4 | 33021232021102030123 |
5 | 114024414340410321 |
6 | 2114200124440231 |
7 | 135140436040123 |
oct | 17115611221433 |
9 | 3615532862811 |
10 | 1041230013211 |
11 | 37164621a083 |
12 | 1499699a9077 |
13 | 7725912056b |
14 | 38578117c83 |
15 | 1c141216791 |
hex | f26e25231b |
1041230013211 has 2 divisors, whose sum is σ = 1041230013212. Its totient is φ = 1041230013210.
The previous prime is 1041230013209. The next prime is 1041230013223. The reversal of 1041230013211 is 1123100321401.
1041230013211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1041230013211 - 21 = 1041230013209 is a prime.
It is a super-2 number, since 2×10412300132112 (a number of 25 digits) contains 22 as substring.
Together with 1041230013209, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1041230013311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520615006605 + 520615006606.
It is an arithmetic number, because the mean of its divisors is an integer number (520615006606).
Almost surely, 21041230013211 is an apocalyptic number.
1041230013211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041230013211 is an equidigital number, since it uses as much as digits as its factorization.
1041230013211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1041230013211 its reverse (1123100321401), we get a palindrome (2164330334612).
The spelling of 1041230013211 in words is "one trillion, forty-one billion, two hundred thirty million, thirteen thousand, two hundred eleven".
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