Base | Representation |
---|---|
bin | 1001011110000100111101… |
… | …0110111010111110100111 |
3 | 1100212102001022212221210102 |
4 | 2113201033112322332213 |
5 | 2331043424011244221 |
6 | 34051205341414315 |
7 | 2123160203556542 |
oct | 227411726727647 |
9 | 40772038787712 |
10 | 10412332134311 |
11 | 335493304a458 |
12 | 1201b90b6a39b |
13 | 5a6b5669a753 |
14 | 27dd61089859 |
15 | 130cae31730b |
hex | 9784f5bafa7 |
10412332134311 has 2 divisors, whose sum is σ = 10412332134312. Its totient is φ = 10412332134310.
The previous prime is 10412332134287. The next prime is 10412332134329. The reversal of 10412332134311 is 11343123321401.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10412332134311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10412332134341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206166067155 + 5206166067156.
It is an arithmetic number, because the mean of its divisors is an integer number (5206166067156).
Almost surely, 210412332134311 is an apocalyptic number.
10412332134311 is a deficient number, since it is larger than the sum of its proper divisors (1).
10412332134311 is an equidigital number, since it uses as much as digits as its factorization.
10412332134311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 10412332134311 its reverse (11343123321401), we get a palindrome (21755455455712).
The spelling of 10412332134311 in words is "ten trillion, four hundred twelve billion, three hundred thirty-two million, one hundred thirty-four thousand, three hundred eleven".
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