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104124130320257 is a prime number
BaseRepresentation
bin10111101011001101001001…
…110011001101111110000001
3111122200011120200002211221122
4113223031021303031332001
5102121432204330222012
61005241544244202025
730634502005360655
oct2753151163157601
9448604520084848
10104124130320257
11301a4883067683
12b817b54699315
134613b2ba48908
141b9d8c5c52a65
15c08793148e72
hex5eb349ccdf81

104124130320257 has 2 divisors, whose sum is σ = 104124130320258. Its totient is φ = 104124130320256.

The previous prime is 104124130320169. The next prime is 104124130320293. The reversal of 104124130320257 is 752023031421401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72133070348161 + 31991059972096 = 8493119^2 + 5656064^2 .

It is a cyclic number.

It is not a de Polignac number, because 104124130320257 - 212 = 104124130316161 is a prime.

It is not a weakly prime, because it can be changed into another prime (104124130350257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52062065160128 + 52062065160129.

It is an arithmetic number, because the mean of its divisors is an integer number (52062065160129).

Almost surely, 2104124130320257 is an apocalyptic number.

It is an amenable number.

104124130320257 is a deficient number, since it is larger than the sum of its proper divisors (1).

104124130320257 is an equidigital number, since it uses as much as digits as its factorization.

104124130320257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 104124130320257 its reverse (752023031421401), we get a palindrome (856147161741658).

The spelling of 104124130320257 in words is "one hundred four trillion, one hundred twenty-four billion, one hundred thirty million, three hundred twenty thousand, two hundred fifty-seven".