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10412515522433 is a prime number
BaseRepresentation
bin1001011110000101101001…
…0010011111011110000001
31100212102112002222001000002
42113201122102133132001
52331044312433204213
634051235452205345
72123164561416023
oct227413222373601
940772462861002
1010412515522433
113354a17616692
121202022469855
135a6b8568982b
1427dd7b586013
15130cc048e658
hex9785a49f781

10412515522433 has 2 divisors, whose sum is σ = 10412515522434. Its totient is φ = 10412515522432.

The previous prime is 10412515522429. The next prime is 10412515522463. The reversal of 10412515522433 is 33422551521401.

10412515522433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5530855057729 + 4881660464704 = 2351777^2 + 2209448^2 .

It is a cyclic number.

It is not a de Polignac number, because 10412515522433 - 22 = 10412515522429 is a prime.

It is not a weakly prime, because it can be changed into another prime (10412515522403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206257761216 + 5206257761217.

It is an arithmetic number, because the mean of its divisors is an integer number (5206257761217).

Almost surely, 210412515522433 is an apocalyptic number.

It is an amenable number.

10412515522433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10412515522433 is an equidigital number, since it uses as much as digits as its factorization.

10412515522433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 10412515522433 in words is "ten trillion, four hundred twelve billion, five hundred fifteen million, five hundred twenty-two thousand, four hundred thirty-three".