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10413034204427 is a prime number
BaseRepresentation
bin1001011110000111100100…
…1101000110110100001011
31100212110212020221210221022
42113201321031012310023
52331101343224020202
634051403141303055
72123213460222311
oct227417115066413
940773766853838
1010413034204427
113355163383098
121202148104a8b
135a6c38c8315a
1427ddca4020b1
15130d00c97ea2
hex97879346d0b

10413034204427 has 2 divisors, whose sum is σ = 10413034204428. Its totient is φ = 10413034204426.

The previous prime is 10413034204423. The next prime is 10413034204429. The reversal of 10413034204427 is 72440243031401.

10413034204427 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10413034204427 - 22 = 10413034204423 is a prime.

Together with 10413034204429, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10413034204423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206517102213 + 5206517102214.

It is an arithmetic number, because the mean of its divisors is an integer number (5206517102214).

Almost surely, 210413034204427 is an apocalyptic number.

10413034204427 is a deficient number, since it is larger than the sum of its proper divisors (1).

10413034204427 is an equidigital number, since it uses as much as digits as its factorization.

10413034204427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 35.

Adding to 10413034204427 its reverse (72440243031401), we get a palindrome (82853277235828).

The spelling of 10413034204427 in words is "ten trillion, four hundred thirteen billion, thirty-four million, two hundred four thousand, four hundred twenty-seven".