Base | Representation |
---|---|
bin | 110000011111011000… |
… | …0111010010001110101 |
3 | 100221210011011002002101 |
4 | 1200332300322101311 |
5 | 3201230322132432 |
6 | 115500534542101 |
7 | 10344331205065 |
oct | 1407660722165 |
9 | 327704132071 |
10 | 104132224117 |
11 | 40186a20259 |
12 | 18221807931 |
13 | 9a8694807c |
14 | 507bb933a5 |
15 | 2a96dcc4e7 |
hex | 183ec3a475 |
104132224117 has 2 divisors, whose sum is σ = 104132224118. Its totient is φ = 104132224116.
The previous prime is 104132224057. The next prime is 104132224123. The reversal of 104132224117 is 711422231401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95625666756 + 8506557361 = 309234^2 + 92231^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-104132224117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104132224187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52066112058 + 52066112059.
It is an arithmetic number, because the mean of its divisors is an integer number (52066112059).
Almost surely, 2104132224117 is an apocalyptic number.
It is an amenable number.
104132224117 is a deficient number, since it is larger than the sum of its proper divisors (1).
104132224117 is an equidigital number, since it uses as much as digits as its factorization.
104132224117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 104132224117 its reverse (711422231401), we get a palindrome (815554455518).
The spelling of 104132224117 in words is "one hundred four billion, one hundred thirty-two million, two hundred twenty-four thousand, one hundred seventeen".
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