Base | Representation |
---|---|
bin | 11110010011110001111… |
… | …00110101101100110111 |
3 | 10200120001202002102211111 |
4 | 33021320330311230313 |
5 | 114030302243101101 |
6 | 2114230122215451 |
7 | 135145066665355 |
oct | 17117074655467 |
9 | 3616052072744 |
10 | 1041411300151 |
11 | 3717295906a2 |
12 | 1499ba654587 |
13 | 77287855141 |
14 | 385942287d5 |
15 | 1c1520c6251 |
hex | f278f35b37 |
1041411300151 has 2 divisors, whose sum is σ = 1041411300152. Its totient is φ = 1041411300150.
The previous prime is 1041411300113. The next prime is 1041411300157. The reversal of 1041411300151 is 1510031141401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1041411300151 - 223 = 1041402911543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1041411300157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520705650075 + 520705650076.
It is an arithmetic number, because the mean of its divisors is an integer number (520705650076).
Almost surely, 21041411300151 is an apocalyptic number.
1041411300151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041411300151 is an equidigital number, since it uses as much as digits as its factorization.
1041411300151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 1041411300151 its reverse (1510031141401), we get a palindrome (2551442441552).
The spelling of 1041411300151 in words is "one trillion, forty-one billion, four hundred eleven million, three hundred thousand, one hundred fifty-one".
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