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10414204103131 is a prime number
BaseRepresentation
bin1001011110001011111011…
…1011111010100111011011
31100212120212210022211020221
42113202332323322213123
52331111242222300011
634052115212300511
72123254454210563
oct227427673724733
940776783284227
1010414204103131
11335570379a324
121202413a71737
135a70944684ca
1428009b937da3
15130d6d839971
hex978beefa9db

10414204103131 has 2 divisors, whose sum is σ = 10414204103132. Its totient is φ = 10414204103130.

The previous prime is 10414204103119. The next prime is 10414204103141. The reversal of 10414204103131 is 13130140241401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10414204103131 - 25 = 10414204103099 is a prime.

It is a super-2 number, since 2×104142041031312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10414204103096 and 10414204103105.

It is not a weakly prime, because it can be changed into another prime (10414204103101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5207102051565 + 5207102051566.

It is an arithmetic number, because the mean of its divisors is an integer number (5207102051566).

Almost surely, 210414204103131 is an apocalyptic number.

10414204103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10414204103131 is an equidigital number, since it uses as much as digits as its factorization.

10414204103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10414204103131 its reverse (13130140241401), we get a palindrome (23544344344532).

The spelling of 10414204103131 in words is "ten trillion, four hundred fourteen billion, two hundred four million, one hundred three thousand, one hundred thirty-one".