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1041431312431 is a prime number
BaseRepresentation
bin11110010011110100010…
…01001011100000101111
310200120010010202011112001
433021322021023200233
5114030322403444211
62114232115153131
7135145432045246
oct17117211134057
93616103664461
101041431312431
1137173990a174
12149a052a57a7
137728ba41023
1438596b5795d
151c153c2aac1
hexf27a24b82f

1041431312431 has 2 divisors, whose sum is σ = 1041431312432. Its totient is φ = 1041431312430.

The previous prime is 1041431312407. The next prime is 1041431312437. The reversal of 1041431312431 is 1342131341401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1041431312431 - 213 = 1041431304239 is a prime.

It is a super-2 number, since 2×10414313124312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1041431312431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1041431312437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520715656215 + 520715656216.

It is an arithmetic number, because the mean of its divisors is an integer number (520715656216).

Almost surely, 21041431312431 is an apocalyptic number.

1041431312431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041431312431 is an equidigital number, since it uses as much as digits as its factorization.

1041431312431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1041431312431 its reverse (1342131341401), we get a palindrome (2383562653832).

The spelling of 1041431312431 in words is "one trillion, forty-one billion, four hundred thirty-one million, three hundred twelve thousand, four hundred thirty-one".