Base | Representation |
---|---|
bin | 11110010011110100010… |
… | …01001011100000101111 |
3 | 10200120010010202011112001 |
4 | 33021322021023200233 |
5 | 114030322403444211 |
6 | 2114232115153131 |
7 | 135145432045246 |
oct | 17117211134057 |
9 | 3616103664461 |
10 | 1041431312431 |
11 | 37173990a174 |
12 | 149a052a57a7 |
13 | 7728ba41023 |
14 | 38596b5795d |
15 | 1c153c2aac1 |
hex | f27a24b82f |
1041431312431 has 2 divisors, whose sum is σ = 1041431312432. Its totient is φ = 1041431312430.
The previous prime is 1041431312407. The next prime is 1041431312437. The reversal of 1041431312431 is 1342131341401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1041431312431 - 213 = 1041431304239 is a prime.
It is a super-2 number, since 2×10414313124312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1041431312431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1041431312437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520715656215 + 520715656216.
It is an arithmetic number, because the mean of its divisors is an integer number (520715656216).
Almost surely, 21041431312431 is an apocalyptic number.
1041431312431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041431312431 is an equidigital number, since it uses as much as digits as its factorization.
1041431312431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 1041431312431 its reverse (1342131341401), we get a palindrome (2383562653832).
The spelling of 1041431312431 in words is "one trillion, forty-one billion, four hundred thirty-one million, three hundred twelve thousand, four hundred thirty-one".
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