104213004041 has 2 divisors, whose sum is σ = 104213004042. Its totient is φ = 104213004040.

The previous prime is 104213004011. The next prime is 104213004043. The reversal of 104213004041 is 140400312401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74016643600 + 30196360441 = 272060^2 + 173771^2 .

It is a cyclic number.

It is not a de Polignac number, because 104213004041 - 2⁶ = 104213003977 is a prime.

It is a super-7 number, since 7×104213004041⁷ (a number of 78 digits) contains 7777777 as substring. Note that it is a super-d number also for d = 2.

Together with 104213004043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (104213004043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52106502020 + 52106502021.

It is an arithmetic number, because the mean of its divisors is an integer number (52106502021).

Almost surely, 2^104213004041 is an apocalyptic number.

It is an amenable number.

104213004041 is a deficient number, since it is larger than the sum of its proper divisors (1).

104213004041 is an equidigital number, since it uses as much as digits as its factorization.

104213004041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 104213004041 its reverse (140400312401), we get a palindrome (244613316442).

The spelling of 104213004041 in words is "one hundred four billion, two hundred thirteen million, four thousand, forty-one".