Base | Representation |
---|---|
bin | 10111101100100001000100… |
… | …111001100100011101110011 |
3 | 111122222210011201220102120221 |
4 | 113230201010321210131303 |
5 | 102124421232024144103 |
6 | 1005351210111113511 |
7 | 30644142035461534 |
oct | 2754410471443563 |
9 | 448883151812527 |
10 | 104214242412403 |
11 | 3022a014a89202 |
12 | b831502b12897 |
13 | 461c48cb565b6 |
14 | 1ba3dd39ac68b |
15 | c0acb92681bd |
hex | 5ec844e64773 |
104214242412403 has 2 divisors, whose sum is σ = 104214242412404. Its totient is φ = 104214242412402.
The previous prime is 104214242412377. The next prime is 104214242412419. The reversal of 104214242412403 is 304214242412401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 104214242412403 - 29 = 104214242411891 is a prime.
It is not a weakly prime, because it can be changed into another prime (104214242410403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52107121206201 + 52107121206202.
It is an arithmetic number, because the mean of its divisors is an integer number (52107121206202).
Almost surely, 2104214242412403 is an apocalyptic number.
104214242412403 is a deficient number, since it is larger than the sum of its proper divisors (1).
104214242412403 is an equidigital number, since it uses as much as digits as its factorization.
104214242412403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 49152, while the sum is 34.
Adding to 104214242412403 its reverse (304214242412401), we get a palindrome (408428484824804).
The spelling of 104214242412403 in words is "one hundred four trillion, two hundred fourteen billion, two hundred forty-two million, four hundred twelve thousand, four hundred three".
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