Base | Representation |
---|---|
bin | 1001011110101101001110… |
… | …1100110111010001011011 |
3 | 1100220102221201100000212112 |
4 | 2113223103230313101123 |
5 | 2331233043424212103 |
6 | 34100154151302535 |
7 | 2124022120456316 |
oct | 227532354672133 |
9 | 40812851300775 |
10 | 10423142413403 |
11 | 3359480186105 |
12 | 12040a937aa4b |
13 | 5a7b8a1c96b5 |
14 | 2806a8a9197d |
15 | 1311e33cccd8 |
hex | 97ad3b3745b |
10423142413403 has 2 divisors, whose sum is σ = 10423142413404. Its totient is φ = 10423142413402.
The previous prime is 10423142413399. The next prime is 10423142413429. The reversal of 10423142413403 is 30431424132401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10423142413403 - 22 = 10423142413399 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10423142413403.
It is not a weakly prime, because it can be changed into another prime (10423142413433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211571206701 + 5211571206702.
It is an arithmetic number, because the mean of its divisors is an integer number (5211571206702).
Almost surely, 210423142413403 is an apocalyptic number.
10423142413403 is a deficient number, since it is larger than the sum of its proper divisors (1).
10423142413403 is an equidigital number, since it uses as much as digits as its factorization.
10423142413403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 10423142413403 its reverse (30431424132401), we get a palindrome (40854566545804).
The spelling of 10423142413403 in words is "ten trillion, four hundred twenty-three billion, one hundred forty-two million, four hundred thirteen thousand, four hundred three".
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