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1042321307 is a prime number
BaseRepresentation
bin111110001000001…
…000111110011011
32200122022102000212
4332020020332123
54113313240212
6251232321335
734554404426
oct7610107633
92618272025
101042321307
114953aa475
122510a324b
13137c37491
149c6069bd
1561790e22
hex3e208f9b

1042321307 has 2 divisors, whose sum is σ = 1042321308. Its totient is φ = 1042321306.

The previous prime is 1042321283. The next prime is 1042321309. The reversal of 1042321307 is 7031232401.

It is a strong prime.

It is an emirp because it is prime and its reverse (7031232401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1042321307 - 210 = 1042320283 is a prime.

Together with 1042321309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1042321309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521160653 + 521160654.

It is an arithmetic number, because the mean of its divisors is an integer number (521160654).

Almost surely, 21042321307 is an apocalyptic number.

1042321307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1042321307 is an equidigital number, since it uses as much as digits as its factorization.

1042321307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 23.

The square root of 1042321307 is about 32285.0012699396. The cubic root of 1042321307 is about 1013.9126430455.

Adding to 1042321307 its reverse (7031232401), we get a palindrome (8073553708).

The spelling of 1042321307 in words is "one billion, forty-two million, three hundred twenty-one thousand, three hundred seven".